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Q1. What is the r.m.s. voltage when the peak voltage of an a.c. supply is 350 V?

Solution

begin mathsize 12px style Given colon
straight E subscript 0 equals 350 space straight V
straight E subscript straight v equals ?
straight E subscript straight v equals fraction numerator straight E subscript 0 over denominator square root of 2 end fraction
straight E subscript straight v equals fraction numerator straight E subscript 0 over denominator square root of 2 end fraction times fraction numerator square root of 2 over denominator square root of 2 end fraction equals fraction numerator straight E subscript 0 cross times 1.414 over denominator 2 end fraction equals fraction numerator 350 cross times 1.414 over denominator 2 end fraction
straight E subscript straight v equals 247.45 space straight V
end style
Q2. State the factors on which inductive reactance of an ac circuit depends.

Solution

The inductive reactance of an ac circuit depends on: Frequency Inductance
Q3. What is the phase difference between E and I in a a.c. circuit with (a)Resistance only (b)Inductor only (c)Capacitance only

Solution

The phase difference between E and I in a a.c. circuit with (a)Resistance only: E and I are in phase (b) Inductor only: I lags behind the voltage by a phase difference of 90º. (c) Capacitance only: I leads the voltage by a phase difference of 90º.
Q4. A resistor of 12 Ω and inductance 2 H are connected in series to a 220 V, 50 Hz a.c. source. Find the total impedance of LR circuit.

Solution

Given: R=12 Ω L=2 H ν=50 Hz  Impedance of LR circuit is given as, begin mathsize 12px style straight Z equals square root of straight R squared plus straight X subscript straight L superscript 2 end root equals square root of straight R squared plus left parenthesis ωL right parenthesis squared end root
straight Z equals square root of 12 squared plus left parenthesis 2 cross times straight pi space cross times 50 cross times 2 right parenthesis squared end root
straight Z equals 628.11 space straight capital omega end style
Q5. Define power factor. State the conditions under which it is (i) maximum and (ii) minimum.

Solution

The power factor(cosΦ) is the ratio of resistance and impedance of an ac circuit i.e, begin mathsize 12px style Power space factor. space cos space straight ϕ equals straight R over straight Z end styleMaximum Power factor is 1 when Z = R i.e, when circuit is purely resistive. Minimum power factor is 0 when R = 0 i.e., when circuit is purely inductive
Q6. Find the virtual current given the r.m.s voltage is 220 V for 100 Ω resistance?

Solution

Q7. What is susceptance? What is its unit?

Solution

Susceptance is the reciprocal of reactance. Its unit is mho or ohm-1 or Siemen.
Q8. What are the values of power factor at generation stage and consumption stage in an ac circuit?

Solution

Q9. What is Q factor of series resonant circuit and what will happen to the Q factor if the resistance increases?

Solution

Q factor of series resonant circuit is defind as the ratio of the voltage developed across the inductance or capacitance at resonance to the impressed voltage, which is the voltage applied across R.   begin mathsize 11px style straight Q equals 1 over straight R square root of straight L over straight C end root
rightwards double arrow straight Q proportional to 1 over straight R end style Q is inversely proportional to R. So, if R increases Q factor of circuit decreases or if R decreases Q increases.
Q10. State the factors on which the power factor depends?

Solution

Power factor depends on resistance and impedance.
Q11. What is Acceptor Circuit?

Solution

The series resonance circuit is called as ccceptor Ccircuit as it admits maximum current through it.
Q12. Deduce that. in a.c. circuit capacitor only current leads the alternating e.m.f by a phase angle of 90º. 

Solution

 
Q13. What are hot wire instruments?

Solution

Alternating currents and alternating voltages are measure using a.c. ammeter or voltmeter. They are called hot wire instruments and they an measure only the virtual values of alternating currents and voltages
Q14. What is the dimensional formula of begin mathsize 12px style square root of LC end style?

Solution

Dimensional formula Of begin mathsize 12px style square root of LC end style is [M0 L0 T1].
Q15. Which circuit is used as filter circuit or rejector circuit and why?

Solution

Parallel resonant circuit is used as filter circuit because such circuit rejects the currents corresponding to the parallel resonant frequencies and allow other frequencies to pass, hence called as filter circuit or rejector circuit.
Q16. In a series RC circuit, R = 30 Ω, C = 0.25 μF, V = 100 V and ω = 1,00,000 rad /s. Find the current in the circuit and calculate the voltage across the resistor and the capacitor.  

Solution

Given:   R = 30 Ω C = 0.25 μF = 0.25 x 10-6 F V = 100 V ω = 1,00,000 = 105 rad /s Rectance  Xc = begin mathsize 12px style 1 over ωC equals fraction numerator 1 over denominator 10 to the power of 5 space straight x space 0.25 space straight x space 10 to the power of negative 6 end exponent end fraction space equals space 40 space straight capital omega end style Impedance of circuit Z = Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. Current in circuit I = begin mathsize 12px style straight V over straight Z space equals 100 over 50 equals 2 space straight A end style Voltage across resistance VR = RI = 30 × 2 =60 V Voltage across capacitance, VC =  XCI = 40 × 2 = 80V The sum of volatages is more than the applied voltage, this is due to the phase difference of between Voltage VR and V.
Q17. What is Wattless Current or Idle Current?

Solution

The current through a pure capacitance, which consumes no power for its maintenance in circuit is called as Wattless current or Idle current.
Q18. Prove that the current lags behind the e.m.f in a purely inductive ac circuit.

Solution

Q19. An electrical appliance of 120 Ω is connected to 220 V, 50 cycles a.c.? Calculate the average potential difference?

Solution

  
Q20. There are two capacitors A and B. Frequency of A is double than that of B but the capacitance is same. Find the ratio of there rectances.

Solution

Q21. The figure shows a series LCR circuit with L= 5.0 H, C = 80 μF, R = 40Ω connected to variable frequency 240 V source. Calculate (i) The angular frequency of the source which driver the circuit at resonance. (ii) The current at the resonating frequency. (iii) The rms potential drop across the capacitor at resonance.

Solution

L = 5.0 C = 80μF R = 40Ω ε = 240 v. (i) ω = begin mathsize 12px style fraction numerator 1 over denominator square root of LC end fraction end style= angular frequency         =begin mathsize 12px style fraction numerator 1 over denominator square root of 5 space straight x space 80 space straight x space 10 to the power of negative 6 end exponent end root end fraction end style         =begin mathsize 11px style fraction numerator 1 over denominator square root of 4 space straight x space 10 to the power of negative 4 end exponent end root end fraction equals space fraction numerator 1 over denominator 2 space straight x space 10 to the power of negative 2 end exponent end fraction equals 100 over 2 equals 50 Hz. end style (ii) The current at the resonating frequency.       I = Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. = begin mathsize 12px style 240 over 40 end style    therefore I at resanating frquency = 6 A (iii) Vrms = Irms XC        XC = begin mathsize 11px style 1 over ωc equals fraction numerator 1 over denominator 50 space straight x space 80 space straight x space 10 to the power of negative 6 end exponent end fraction end style     begin mathsize 11px style therefore space straight V subscript rms space equals space fraction numerator 6 over denominator 50 space straight x space 80 space straight x space 10 to the power of negative 6 end exponent end fraction equals space fraction numerator 6 over denominator 4000 space straight x space 10 to the power of negative 6 end exponent end fraction equals space fraction numerator 6 straight x space 10 cubed over denominator 42 end fraction end style= 142.86 V
Q22. What is a parallel resonance circuit? Why is it called so?

Solution

Parallel resonant circuit is the one in which inductor and condenser is joined in parallel to a source of alternating e.m.f. In a parallel resonant circuit the frequency of applied alternating e.m.f. is equal to the natural frequency of oscillation of circuit. Hence it is called parallel resonant circuit.   begin mathsize 11px style straight nu equals fraction numerator 1 over denominator 2 straight pi square root of LC end fraction end style
Q23. In a circuit a coil of resistance 100 Ω and inductance 0.1 H are connected across an ac voltage of frequency 100/2π Hz. What is the phase difference?

Solution

Given: R=100 Ω L=1 H ν=100/2π Hz Phase angle is given as, begin mathsize 12px style tan space straight ϕ equals 2 straight pi cross times fraction numerator 100 over denominator 2 straight pi end fraction cross times 1 over 100
tan space straight ϕ equals 1
straight ϕ equals 45 degree end style
Q24. A 100 Ω iron is connected to a 200 V supply with 50 Hz frequency. Find the rms value of current and the net power consumed over full cycle.

Solution

Given: begin mathsize 11px style straight E subscript straight v equals 200 space straight V
straight R equals 100 space straight capital omega end style


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